Question

If x=√3+√2/√3-√2 and y=√3-√2/√3+√2,find the value of x²+xy-y²

Answer 1

Answer:

a=(√3+√2)/(√3-√2)……b=(√3-√2)/(√3+√2)

a^2=(3+2+2√6)/(3+2–2√6)

…=(5+2√6)/(5-2√6)……b^2=(5–2√6)/(5+2√6)

a^2+b^2=(5+2√6)/5–2√6)+(5–2√6)/5+2√6)

…………={(5+2√6)^2+(5–2√6)^2}/5^2–4*6

…………..=(25+4*6+20√6+25+4*6–20√6)/25–24

……”……=49+49=98

Step-by-step explanation:

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