If x = √3−√2 √3+ √2 and y= √3+√2 √3−√2 , find the value of x2 +y2 + xy. Also find the value of x3 – y 3 using the identity
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x=3+23−2×3−23−2 [Rationalising the equation]
⇒(3)2−(2)23(3−2)−2(3−2)
=3−23−23−23+2
=5−26
Similarly for y
y=5−2
hope it helps you
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