if x = √3 + √2 /√3-√2 and y = √3 - √2 / √3 + √2 . show that x^2 + y^2 +100.
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x^2 + y^2 +100
= (√3 + √2 /√3-√2)² + (√3 - √2 / √3 + √2)²
= (5+2√6 / 5-2√6) + (5-2√6 / 5+2√6)
= 100
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