Question

If x=√3+√2/√3-√2 and y=√3-√2/√3+√2 then find x^2 +y^2-10xy

Answer 1

Hello,

Please refer the above photograph for the used process

Hope this will be helping you ✌️

Answer 2

Step-by-step explanation:

$x = \frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{3} - \sqrt{2} } \\ \\ y = \frac{ \sqrt{3} - \sqrt{2} }{ \sqrt{3} + \sqrt{2} } \\ \\ xy = 1 \\ \\ x + y = \frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{3} - \sqrt{2} } + \frac{ \sqrt{3} - \sqrt{2} }{ \sqrt{3} + \sqrt{2} } \\ \\ x + y = \frac{( { \sqrt{3} + \sqrt{2} })^{2} + ( { \sqrt{3} - \sqrt{2} })^{2} }{3 - 2} \\ \\ x + y = 2(3 + 2) = 10 \\ \\ \\ {x}^{2} + {y}^{2} - 10xy = ( {x + y})^{2} - 12xy \\ = {10}^{2} - 12 \times 1 \\ = 100 - 12 \\ = 88$