Question

if x=√3-√2÷√3+√2, y=√3+√2÷√3-√2 then find x+y​

Answer 1

= $\frac{\sqrt{3}-\sqrt{2} }{\sqrt{3}+\sqrt{2} }+\frac{\sqrt{3}+\sqrt{2} }{\sqrt{3}-\sqrt{2} }$

= $\frac{(\sqrt{3}-\sqrt{2})^{2} +(\sqrt{3}+\sqrt{2})^{2} }{(\sqrt{3}+\sqrt{2})(\sqrt{3}-\sqrt{2}) }$

= $\frac{5-2\sqrt{3}\sqrt{2}+5+\sqrt{3}\sqrt{2} }{3-2}$

= $\frac{10}{1}$

= $10$

Hope this will help you

Mark me as Brainliest