Question

if x=√3+√2/√3-√2and y=√3-√2/√3+√2,find the value of (x+y)(x+y)​

Answer 1

Step-by-step explanation:

$x + y = \frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{3} - \sqrt{2} } + \frac{ \sqrt{3} - \sqrt{2} }{ \sqrt{3} + \sqrt{2} } =$

$\frac{ {( \sqrt{3} + \sqrt{2}) }^{2} + {( \sqrt{3} - \sqrt{2})}^{2} }{( \sqrt{3} + \sqrt{2})( \sqrt{3} - \sqrt{2})} = \frac{3 + 2 + 2 \sqrt{6} + 3 + 2 - 2 \sqrt{6} }{3 - 2}$

$= 10$

$(x + y)(x + y) = {(x + y)}^{2} = {10}^{2} =$

$100$

Hope it helps you.