Math, asked by manannehru438, 1 year ago

If x=√3-√2/√3+√2and y=√3+√2/√3-√2. Then find the value of x2,y2and xy

Answers

Answered by laxmanacharysangoju

1

Answer:

x^2=49-20√6
y^2=49+20√6
xy=1

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