If x= 3+2√3 find the value of x²+1/x² and x⁴+1/x⁴
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Step-by-step explanation:
x-1/x = 3
(x-1/x )^2 = x^2+ 1/x^2- 2
(x - 1/x )^2 = (3)^2
so x^2+ 1/x^2 -2 = 9
so x^2 + 1^2 will be 9+2 = 11
x^4 + 1/ x ^4 will be x^2+ 1/ x^2 whole square
so by squaring on both sides we get (x)^2 + (1/ x)^2 =(11)^2
so x^4 + 1/ x^4 +2 = 121
x ^4 + 1/ x ^4 will be 121-2=119
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