Question

if x+3/2 +3x= 5(x-3)+ x+23/5, then what is the value of x?​

Answer 1

Question :- if x+3/2 +3x= 5(x-3)+ x+23/5, then what is the value of x ?

Solution :-

→ x + (3/2) + 3x= 5(x-3) + x + 23/5

x will be cancel from both sides,

→ (3/2) + 3x = 5(x-3) + 23/5

→ (3/2) + 3x = 5x - 15 + 23/5

→ 5x - 3x = (3/2) + 15 - (23/5)

Taking LCM of RHS denominator now,

→ 2x = (3*5 + 15*10 - 23*2)/10

→ 2x = (15 + 150 - 46) / 10

→ 2x = (165 - 46) / 10

→ 2x = 119/10

Taking 2 RHS side , it will be in denominator,

→ x = (119) / (10 *2)

→ x = (119/20) (Ans.)

Answer 2

Answer:

hope u understand

so answer is 7