Question

If x=√3+√2 and y=1/x find the value of ( x +y)2 and (x-y)2.​

Answer 1

Step-by-step explanation:

$x = \sqrt{3} + \sqrt{2} \\ y = \frac{1}{x} \\ (x + y) {}^{2} \\ = ( \sqrt{3} + \sqrt{2} + \frac{1}{ \sqrt{3} + \sqrt{2} }) {}^{2} \\ (x - y) {}^{2} \\ = ( \sqrt{3} + \sqrt{2} - \frac{1}{ \sqrt{3} + \sqrt{2} } ) {}^{2}$

Answer 2

Answer:

here's your answer

hope it will help you