Question

if x=-3/2 and y=-5/7 is a solution of the equation 2x+3k1=0 and 7y-5k2=0,find the value of k1 and k2​

Answer 1

Step-by-step explanation:

2x+3k1=0

2(-3/2)+3k1=0 [x=-3/2]

-(3*2/2)+3k1=0

-3+3k1=0

3k1=3

k1=3/3

k1=1

7y-5k2=0

7(-5/7)-5k2=0 [y=-5/7]

-(5*7/7)-5k2=0

-5-5k2=0

-5k2=5

k2=5/(-5)

k2=-5/5

k2=-1

The value of k1=1 and k2=-1