if x =3+√2 , check whether x+ 1 by X is rational number or irrational number
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3+√2+1/3+√2
=4+√2/3+√2
Rationalize the denominator
Rationalizing factor= 3-√2
(4+√2)(3-√2)/ (3+√2)(3-√2)
=12-4√2+3√2-2/ ()-(√)
=10-√2/9-2
=10-√2/7
10-√2/7 is an irrational number.
Checking.
Lets Assume that 10-√2/7 is a rational number
10-√2/7= a/b, where a and b are co-prime integers.
10-√2= 7a/b
-(√2+10)= 7a/b
-√2=7a/b-10
-√2=7a-10b/b
Changing the negative sign of √2
√2= 10b-7a/b
Here, 10b-7a/b is a rational number, but this contradicts the fact that √2 is irrational.
Thus, Our Assumption is wrong, i.e., 10-√2/7 is irrational
Step-by-step explanation:
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