if x= 3+√2, find out value of √x+1/√x
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Answered by
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Answer:
Step-by-step explanation:
BrainlyQueen01Maths AryaBhatta
Hey mate!
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Given :
x = 2 + \sqrt{3}
To find :
x + \frac{1}{x}
Solution :
x = 2 + \sqrt{3} \\ \\ \frac{1}{x} = \frac{1}{2 + \sqrt{3} } \times \frac{2 - \sqrt{3} }{2 - \sqrt{3} } \\ \\ \frac{1}{x} = \frac{2 - \sqrt{3} }{(2) {}^{2} - ( \sqrt{3}) {}^{2} } \\ \\ \frac{1}{x} = \frac{2 - \sqrt{3} }{4 - 3} \\ \\ \frac{1}{x} = 2 - \sqrt{ 3}
Now,
x + \frac{1}{x} \\ \\ \implies 2 + \cancel{\sqrt{3}} + 2 - \cancel{ \sqrt{3}} \\ \\ \implies 2 + 2 \\ \\ \implies 4
Hence,
The answer is 4.
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Thanks for the question !
Answered by
0
Answer:
3+*2+1/3+*2 = 4+*2/3+*2
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