Math, asked by vijayalakshmijaisank, 9 months ago

if x=√3-√2 find the value of (x+1/x) ^2
Please answer immediately. ☺

Answers

Answered by Archita893
1

heya user !

a= 2 ,x = 2

Step-by-step explanation:

3–2√2 = 1–2√2+2= 1^2–2×1×√2+(√2)^2= (1-√2)^2

x=(1-√2)^2 , √x=1-√2

√x-1/√x=1-√2–1/(1-√2)=(1-√2-√2+2–1)/÷(1-√2)

=(2–2√2)/(1-√2)=2(1-√2)/(1-√2)=2

other procedure,

√x-1/√x=(x-1)/√x=(3–2√2–1)/√x= (2–2√2)/√x

=2(1-√2)/√x=a ( say) , a^2=4(1-√2)^2/x

=4(1–2√2+2)/(3–2√2) = 4(3–2√2)/(3–2√2)=4

a=2 , √x-1/√x=2 ans

Answered by Uniquedosti00017
1

Answer:

the answer is 12.

refer to the attachment for the solution

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