if x=√3-√2 find the value of (x+1/x) ^2
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heya user !
a= 2 ,x = 2
Step-by-step explanation:
3–2√2 = 1–2√2+2= 1^2–2×1×√2+(√2)^2= (1-√2)^2
x=(1-√2)^2 , √x=1-√2
√x-1/√x=1-√2–1/(1-√2)=(1-√2-√2+2–1)/÷(1-√2)
=(2–2√2)/(1-√2)=2(1-√2)/(1-√2)=2
other procedure,
√x-1/√x=(x-1)/√x=(3–2√2–1)/√x= (2–2√2)/√x
=2(1-√2)/√x=a ( say) , a^2=4(1-√2)^2/x
=4(1–2√2+2)/(3–2√2) = 4(3–2√2)/(3–2√2)=4
a=2 , √x-1/√x=2 ans
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Answer:
the answer is 12.
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