Question

If x =3/2 is a root of quadratic equation kx^2+5x -21=0 then find the value of k

Answer 1

Step-by-step explanation:

hope this answer will be helpful

Answer 2

The value of k is 6.

Step-by-step explanation:

Given : If $x=\frac{3}{2}$ is a root of quadratic equation $kx^2+5x -21=0$.

To find : The value of k ?

Solution :

We put the root x in the equation to get the value of k,

$k(\frac{3}{2})^2+5(\frac{3}{2}) -21=0$

$k(\frac{9}{4})+\frac{15}{2} -21=0$

$\frac{9}{4}k=21-\frac{15}{2}$

$\frac{9}{4}k=\frac{27}{2}$

$k=\frac{27\times 4}{2\times 9}$

$k=3\times 2$

$k=6$

The value of k is 6.

#Learn more

Find the value of k for which the Roots are real and equal of quadratic equation kx²-5x+k =0

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