if x=3+2 root 2 , evaluate x+1/x and x^2+1/x^2
Answers
Answered by
0
Answer:
Step-by-step explanation:
1/x=3-2√2
X+1/x=3+2√2+3-2√2=6
X^2+1/x^2=(x+1/x)^2-2.x.1/x=6^2-2=34
Answered by
2
Answer:
Hey Mate!!
x = 3 + 2√2
⇢ 1/x = 1/(3 + 2√2)
⇢ 1/x = (3 - 2√2)/[(3 + 2√2)(3 - 2√2)]
⇢ 1/x = (3 - 2√2)/[3² + (2√2)²]
⇢ 1/x = (3 - 2√2)/(9 - 8)
⇢ 1/x = (3 - 2√2)/1
⇢ 1/x = 3 - 2√2
⇝ x + 1/x
⇝ 3 + 2√2 + 3 - 2√2
⇝ 6
x² = (3 + 2√2)²
⇢ x² = 3² + 2(3)(2√2) + (2√2)²
⇢ x² = 9 + 12√2 + 8
⇢ x² = 17 + 12√2
1/x² = 1/(17 + 12√2)
⇢ 1/x² = (17 - 12√2)/[(17 + 12√2)(17 - 12√2)]
⇢ 1/x² = (17 - 12√2)/[17² - (12√2)²]
⇢ 1/x² = (17 - 12√2)/(289 - 288)
⇢ 1/x² = (17 - 12√2)/1
⇢ 1/x² = 17 - 12√2
x² + 1/x²
⇝ 17 + 12√2 + 17 - 12√2
⇝ 34
Similar questions
Chemistry,
5 months ago
World Languages,
5 months ago
Social Sciences,
5 months ago
Accountancy,
10 months ago
Math,
10 months ago
CBSE BOARD X,
1 year ago