if x=3-2 root 2,then find the value of root x + 1/root x
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x=3-2√2----(1)
1/x=1/(3-2√2) = (3+2√2)/(3-2√2)(3+2√2)=(3+2√2)/(9-8) =3+2√2---(2)
x+1/x= (1)+(2)= 3-2√2+3+2√2=6
1/x=1/(3-2√2) = (3+2√2)/(3-2√2)(3+2√2)=(3+2√2)/(9-8) =3+2√2---(2)
x+1/x= (1)+(2)= 3-2√2+3+2√2=6
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x=3-2√2----(1)
1/x=1/(3-2√2) = (3+2√2)/(3-2√2)(3+2√2)=(3+2√2)/(9-8) =3+2√2---(2)
x+1/x= (1)+(2)= 3-2√2+3+2√2=6
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