Question

if x= 3+2 root 2 then value of x² -6x+5 is​

Answer 1

Answer:

4

Step-by-step explanation:

x=3+2√2

x^2 = 17+12√2

now

according to the question

x^2-6x+5

=17+12√2 -6(3+2√2) +5

= 4

Answer 2

Given,

The value of x =3+2$\sqrt{2}$.

To Find,

The value of $x^{2}-6x+5$.

Solution,

To find the value we simply have to put the value of x in the equation.

So,

$x^{2}-6x+5$

=(3+2$\sqrt{2}$$)^{2}$-6×(3+2$\sqrt{2}$) +5.

={$3^{2}$+2×3×2$\sqrt{2}$+$(2\sqrt{2} )^{2}$}-18-12$\sqrt[]{2}$+5.

=9+12$\sqrt{2}$+8-18-12$\sqrt{2}$+5.

=9+8+5-18.

=4.

Hence, the value  $x^{2}-6x+5$ is 4.