Question

if x=(3/2) square × (2/3) whole powar 4 find the value of x powar -2​

Answer 1

Answer:

81/16

Step-by-step explanation:

$x =( { \frac{3}{2} })^{2} \times ({ \frac{2}{3} })^{4} \\ = \frac{3}{2} \times \frac{3}{2} \times \frac{2}{3} \times \frac{2}{3} \times \frac{2}{3} \times \frac{2}{3} \\ = ({ \frac{2}{3} )}^{2} \\ = \frac{4}{9}$

Hence,

${x}^{ - 2} = ( { \frac{4}{9} })^{ - 2} \\ = ( { \frac{9}{4} })^{2} \\ = \frac{81}{16}$

☆☆Note:-

${a}^{ - n} = ( { \frac{1}{a} })^{n}$

Answer 2

$\huge \tt \pink {Answer :- }$

$\tt \: x = { (\frac{3}{2} )}^{2} \times ({ \frac{2}{3} })^{4} \\ \tt \: x = \frac{ \cancel{9}}{ \cancel{4}} \times \frac{ \cancel{16} \: \: \small{2}}{ \cancel{81} \: \: \small{9}} \\ \tt \: x = \frac{2}{9} \\ \tt{Now , \: \: we \: \: find \: \: {x}^{ - 2} } \\ \tt = (\frac{2}{9} )^{ - 2} \\ = \tt( { \frac{9}{2}) }^{2} \\ = \tt \: \frac{81}{4} \: \: \: or \: \: \: 20\frac{1}{4} \: \: or \: 20.25$

Hope it's helpful to you :) :)