if x=√3/2 then 1+X/1+√1+x + 1-x/1-√1-x
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x = 3 - 2√2 ----( 1 )
1/x = 1/( 3 - 2√2 )
= ( 3 + 2√2 ) / [ ( 3 - 2√2 )(3+2√2 )]
= ( 3 + 2√2 ) / [ 3² - ( 2√2 )² ]
= ( 3 + 2√2 ) / ( 9 - 8 )
= 3 + 2√2 ----( 2 )
x + 1/x = 3 - 2√2 + 3 + 2√2
= 6 ------( 3 )
x - 1/x = 3 - 2√2 - ( 3 + 2√2 )
= 3 - 2√2 - 3 - 2√2
= - 4√2 ---- ( 4 )
Now ,
x² - 1/x² = ( x + 1/x ) ( x - 1/x )
= 6 × ( - 4√2 )
[ From ( 3 ) and ( 4 ) ]
= - 24√2
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