If x=3/2,then( 8x-3)2/x=12/x
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Given, x +1/2x = 2
Multiplying through by 2x,
2x² + 1 = 4x …………………………………………………………………………………….(1)
Now,
8x³ + 1/x³ = (2x)³ +(1/x)³
(Using the identity a³ + b³ = (a+b) (a² - ab + b²) for a=2x and b=1/x)
= [(2x + 1/x)] [(2x)² - 2x.1/x + (1/x)²]
= [(2x² + 1)/x] [4x² - 2 + 1/x²]
= [(2x² + 1)/x] [(4x⁴ - 2x² + 1)/x²]
= [(2x² + 1)/x] [(2x²)² + 2. 2x².1 + 1² - 6x²)/x²]
= [(2x² + 1)/x] [(2x² + 1)² - 6x²)/x²]
Replacing 2x² + 1 by 4x from (1),
= (4x/x) [(4x)² - 6x²)/x²] = 4(16x² - 6x²)/x²
= 4 (10x²/x²) = 4 . 10 = 40
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