Question

If X^3 - 2ax^2+16 is exactly divisible by (x+2), then the value of 'a' is (a)0 (b)1 (c)2 (d)3

Answer 1

Answer:

1

Step-by-step explanation:

if the equation is exactly divisible by (x+2)

then the value of x will be -2

so , put x= -2 in the equ

(-2)^3 -2a(-2)^2 +16=0

-8 -8a+16=0

a=1