Question

If x=3--2root2,find the value of 1/x

Answer 1

x=3-2√2
Then,
1/x=1/3-2√2
Rationalize the denominator
1/3-2√2×3+2√2/3+2√2
=>3+2√2/3²+(2√2)²
=>3+2√2/9-8
=>3+2√2/1
=>3+2√2

Answer 2

Hi friend
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Your answer
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x = 3 - 2√2

To find : - Value of 1/x .

To find the value of 1/x, we need to rationalise the denominator.

$x = 3 - 2 \sqrt{2} \\ \\ = > \frac{1}{x} = \frac{1}{3 - 2 \sqrt{2} } \\ \\ = > \frac{1}{x} = \frac{1}{(3 - 2 \sqrt{2} )} \times \frac{(3 + 2 \sqrt{2}) }{(3 + 2 \sqrt{2} )} \\ \\ = > \frac{1}{x} = \frac{(3 + 2 \sqrt{2} )}{(3 ){}^{2} - (2 \sqrt{2} ) {}^{2} } \\ \\ = > \frac{1}{x} = \frac{(3 + 2 \sqrt{2} )}{9 - 8} \\ \\ = > \frac{1}{x} = \frac{3 + 2 \sqrt{2} }{1} = 3 + 2 \sqrt{2}$
HOPE IT HELPS