if x=3-2root2,find xcube-1/xcube
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Answer:
we have , x=3-2√2
1/x=1/3-2√2=1/3-2√2×3+2√2/3+2√2
1/x=3+2√2/(3)²-(2√2)²
1/x=3+2√2/9-(4×2)
1/x=3+2√2/9-8
1/x=3+2√2
x-1/x=(3-2√2)-(3+2√2)
x-1/x=3-2√2-3+2√2
x-1/x=3-3-2√2+2√2
x-1/x=0-0
x-1/x=0
hence, x³-1/x³=(x-1/x)³
we know that, x-1/x=0
so, (x-1/x)³=(0)³
(x-1/x)³=0
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