if x^3+2x^2+ax+b is divisible by x^2-x write the values of a and b
Answers
Answered by
1
Answer:
use this identity a square + b square = (a+b) whole square
Step-by-step explanation:
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Answered by
0
Answer:
x3 + x2 -ax + b is divisible by x - x or x(x-1)
x and (x-1) they are the factors of x + x2 -ax
+ b.
O and 1 they are the zeros of x3 + x?-ax + b.
PUTTING x = 0
(0) + -a(0) + b = 0 = b = 0
putting x = 1
(1)3 + (12 - a(1) + b = 0 1+ 1-a + b 0 2 - a + 0 = 0 a = 2
Step-by-step explanation:
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