Question

if[x-3] [2y-8] [2+2] [6]=[5 ,2, - 2 ,a, -4]then find the value of X,y,z and a​

Answer 1

$\textbf{Given:}$

$\left(\begin{array}{cc}x-3&2y-8\\z+2&6\end{array}\right)=\left(\begin{array}{cc}5&2\\-2&a-4\end{array}\right)$

$\textbf{To find:}$

$\text{The values of x,y,z and a}$

$\textbf{Solution:}$

$\text{Consider,}$

$\left(\begin{array}{cc}x-3&2y-8\\z+2&6\end{array}\right)=\left(\begin{array}{cc}5&2\\-2&a-4\end{array}\right)$

$\text{Equating the corresponding elements, we get}$

$\begin{array}{|c|c|}\cline{1-2}&\\x-3=5&2y-8=2\\&\\x=5+3&2y=10\\&\\\bf\,x=8&\bf\,y=5\\\cline{1-2}&\\z+2=-2&a-4=6\\&\\z=-2-2&a=4+6\\&\\\bf\,z=-4&\bf\,a=10\\\cline{1-2}\end{array}$

Answer 2

Answer:

Step-by-step explanation: