Question

if x= 3+3^{1/3} +3^(2/3) THEN
FIND THE VALUE OF x^3 - 9x^2+ 18x +27


options are
1. 39
2. 12
3. 0
4. 48

Answer 1

x = 3 + 3¹/³  + 3²/³

(x - 3)³ = (3¹/³ + 3²/³)³
x³ - 3*x² *3 + 3 x *9 - 3³ = 3 + 3 * 3²/³ * 3²/³ + 3 * 3¹/³ * 3⁴/³  + 3²
x³ - 9 x² + 27 x - 27 = 12 + 3 * 3⁴/³+ 3 * 3⁵/³  = 12 + 3*3* 3¹/³ + 3 * 3 * 3²/³

we add - 9x + 54 to both sides.

x³ - 9 x²  + 18 x + 27
  = 12 + 9 * 3¹/³  + 9 * 3²/³  - 9 x + 54
  = 12 + 9 (x - 3)  - 9 x + 54
  = 12 + 27
   = 39

Answer 2

Answer:0Step-by-step explanation:TAKE X = 3+3^1/3+3^2/3IF WE TAKE (A+B)^3= A^3 + 3AB^2B +3AB^2 +B^3THIS WAY IT CAN BE SEEN IF WE MULTIPLY 3^1/3 WITH3^2/3 GIVES 3 .SO TAKE THE X-3=3^1/3 + 3^2/3 { CUBE BOTH THE SIDES}x^3-27+27x-9x^2=12+9(x-3)=x^3-9x^2+18-27 = 12-27 = x^3 -9x^2 +18x-12 = 0{ HOPE IT HELPS PRESS THE HEART BUTTON AND RATE 5 STAR AND GIVE HEART ❤ AROUND 2,0,00,000,0000 }