if x=√3+√3+√3+............. find value of x
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Solution.
x = root 3 + root 3 + root 3 +...............
a = root 3 [ first term]
r [ common ratio ] = root3 / root3 = 1.
Now,
here 'x' indicates the sum of the given Geometric Progression.
So,
X = a [r^n - 1 ] ÷ r - 1
X = root 3 [ 1^n - 1 ] ÷ (1-1)
X = root 3 [ 1-1 ] ÷ 0
X = root 3 × 0 ÷ 0
X = 0/0
X = 0.
Hope this will help you.......☺☺
☛ ⛧⛧ Mr. Thakur ⛧⛧
x = root 3 + root 3 + root 3 +...............
a = root 3 [ first term]
r [ common ratio ] = root3 / root3 = 1.
Now,
here 'x' indicates the sum of the given Geometric Progression.
So,
X = a [r^n - 1 ] ÷ r - 1
X = root 3 [ 1^n - 1 ] ÷ (1-1)
X = root 3 [ 1-1 ] ÷ 0
X = root 3 × 0 ÷ 0
X = 0/0
X = 0.
Hope this will help you.......☺☺
☛ ⛧⛧ Mr. Thakur ⛧⛧
Anonymous:
So 0/0 is 0 wow
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