Question

if x=3 + 3⅔ + 3⅓ , then the value of x³- 9x² + 18x - 12


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Answer 1

Answer:

x=3+3⅓+3⅔

or,(x−3)=3⅓+3⅔

Therefore,

(x−3)3=(3⅓+3⅔)3

or,x3−27−9x2+27x=3+9+3×3(3⅓+3⅔)

or,x3−27−9x2+27x=12+9(x−3)[Puttingthevalue(x−3)=(3⅓+3⅔)]

or,x3−27−9x2+27x=12+9x−27

or,x3−27−9x2+27x−12−9x+27=0

or,x3−9x2+18x−12=0(Answer)

Answer 2

Hey :-

Solution :-

We have, x = 3 + 32/3

x-3=3³ +31 Cubing on both sides,

(x-3)* = (3³ +31)

2-3³-3×3× x(x-3) = (3³)³ + (3³)³ +3

× 3 × 3(3+3)

2³-27-9x² +27x=3² +3+3× (3¹)(x -

3)

23-27-92²+27x-9-3=9(x-3)

2-39-9x²+27-9x+27= 0 23-92² +18r - 12 = 0

0 will be your answer :')