if √x=3-√3 find the value of √x+1/√x
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2
Step-by-step explanation:
(√x)-(1/√x))^2=x+(1/x)-2*x*(1/x).I.e
(a-b)^2=a*a+b*b-2*a*b.
((√x)-(1/√x))^2=(3–2√2)+(1/3–2√2)-2*(3–2√2)*(1/3–2√2).
Rationalising the above factor (3–2√2) I.e
Multiplying with (3+2√2) in numerator and denominator.so the result be (3+2√2).
((√x)-(1/√x))^2=(3–2√2)+(3+2√2)-2.
((√x)-(1/√x))^2=3+3–2=4.
Applying square root on both sides
(√x)-(1/√x)=2.
So the answer is 2.
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