Question

if x=3/4 and y=-9/8 find the value of( x+y)-¹ and x-¹+y-¹ are they equal?
pls ans in full format​

Answer 1

Answer:

${(x + y)}^{ - 1} = \frac{ - 8}{3}$

${x}^{ - 1} + {y}^{ - 1} = \frac{4}{9}$

and they are not equal

Step-by-step explanation:

here,

$x = \frac{3}{4}$

$y = \frac{ -9}{8}$

${(x + y)}^{ - 1} = {( \frac{3}{4} + ( \frac{ - 9}{8})) }^{ - 1}$

$= {( \frac{3}{4} - \frac{9}{8} ) }^{ - 1}$

$= {( \frac{ - 3}{8}) }^{ - 1}$

$= \frac{ - 8}{3}$

Again,

${x}^{ - 1} + {y}^{ - 1} = {( \frac{3}{4}) }^{ - 1} + {( \frac{ - 9}{ 8}) }^{ - 1}$

$= \frac{4}{3} - \frac{8}{9}$

$= \frac{4}{9}$