Question

if x = (3/5)^-2 ÷ (3/5)^0 find the value of x^-2​

Answer 1

Answer:

$x = (\frac{3}{5} )^{ - 2} \div (\frac{3}{5} ) ^{0} \\ \\ (base \: are \: same \:so \: we \: subtract\: the \: exponents) \\ \\ x = - 2 - 0 \\ \\ \huge \bold \blue{ x = - 2} \\ \\ = > so \: the \: value \: of \: {x}^{ - 2} \\ = > {( - 2)}^{ - 2} \\ \\ \\ \huge \bold \green{= > - 0.25}$

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