If x = 3√5, y = 2-√5, Find x²+4xy+y²
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here
x=3 root 5
y=2- root 5
x^2+4xy+y^2
(3 root 5)^2+ 4(3 root 5)(2- root 5)+(2- root 5)^2
45+12 root 5× 8-root 5-1
45-1+96×-5
44-480
-436
x=3 root 5
y=2- root 5
x^2+4xy+y^2
(3 root 5)^2+ 4(3 root 5)(2- root 5)+(2- root 5)^2
45+12 root 5× 8-root 5-1
45-1+96×-5
44-480
-436
Answered by
0
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