If x ^3 + 6 x ^2 + 4 x + k is divisible by ( x + 2 ) , then the value of k is:
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Answered by
2
Answer:
Divide x
3
+6x
2
+4x+k by x+2
x+2
)x
3
+6x
2
+4x+k(
x
2
+4x−6
−(x
3
+2x
2
)
4x
2
+4x+k
−(4x
2
+8x)
−4x+k
−(−4x−8)
k+8
As, x+2 is a factor of the given polynomial, so remainder must be 0.
So, k+8=0 or k=−8
Answered by
0
Step-by-step explanation:
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