Question

if x^{-3} =64 then find the value of x^{3/2} +x^{0}

Answer 1

Step-by-step explanation:

as x^{-3}=64

therefore x^{-3}=4^{3}

so x=4^{6}

now x^[3/2]=[4^{6}]^[3/2]

on opening the brackets the power get multiplied

and we get 4^[9]

now x^0 = 1 (for any number)

so x^[3/2]+x^[0] = 4^[9]+1= 262144+1=262145.

Answer 2

Step-by-step explanation:

x^(-3) = 1/ x³ = 64 = 4³

1/x = 4 = 2²

x = 1/2² =2^(-2)

x^(3/2) = 2^((-2)×3/2)

=2^(-3)=1/8

x^(3/2)+x^0 = 1/8 +1 =1 1/8 =9/8 = 1.125