Question

If x^3-6x^2+11x-6=0 then find the value of (3x-4) by synthetic division​

Answer 1

Answer:

${x}^{3} - 6 {x}^{2} + 11x - 6 = 0 \\ (x - 1)(x - 2)(x - 3) = 0 \\ x = 1 \\ x = 2 \\ x = 3 \\ 3x - 4 = 3 \times 1 - 4 = - 1 \\ 3x - 4 = 3 \times 2 - 4 = 2 \\ 3x - 4 = 3 \times 3 - 4 = 5 \\ anssssssssssss$

Step-by-step explanation:

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