If x^3-6x^2+6x+k is completely divisible by X-3,then find the valu of k.
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2
Answer:
9
Step-by-step explanation:
Given,
p(x)=x^3-6x^2+6x+k
g(x)=x-3
Therefore,
x-3=0
x=3
Substitute x=3 in p(x).
3^3-6(3)^2+6(3)+k=0
27-54+18+k=0
27-36+k=0
-9+k=0
k=9
Therefore k=9.
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