Math, asked by shikhu62, 5 months ago

If x^3-6x^2+6x+k is completely divisible by X-3,then find the valu of k.

Answers

Answered by Gauravreddys

2

Answer:

9

Step-by-step explanation:

Given,

p(x)=x^3-6x^2+6x+k

g(x)=x-3

Therefore,

x-3=0

x=3

Substitute x=3 in p(x).

3^3-6(3)^2+6(3)+k=0

27-54+18+k=0

27-36+k=0

-9+k=0

k=9

Therefore k=9.

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