Question

If x

3 + 6x2

+ kx + 6 is exactly divisible by (x + 2), then k=?​

Answer 1

Answer:

I am sorry I will help you next time

Step-by-step explanation:

please mark me brainlist

Answer 2

Step-by-step explanation:

Given that:-

Given polynomial p(x)=x³+6x²+Kx+6

P(x) is exactly divisible by (x+2)

then by factor theorem

If (x-a) is a factor of p(x) then p(a)=0

=>p(-2)=0

=>(-2)³+6(-2)²+k(-2)+6=0

=>-8+24-2k+6=0

=>30-8-2k=0

=>22-2k=0

=>2k=22

=>k=22/2

=>k=11

The value of k=11