If x = 3+√72, find the value of 4x2+ 1x2
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Answer:
Step-by-step explanation:
x=\frac{3+\sqrt{7} }{2}x=
2
3+
7
∴x^2=\frac{16+6\sqrt{7} }{4} =4+\frac{3\sqrt{7} }{2}x
2
=
4
16+6
7
=4+
2
3
7
\begin{gathered}4*(4+\frac{3\sqrt{7} }{2} )+\frac{2}{8+3\sqrt{7} }\\\end{gathered}
4∗(4+
2
3
7
)+
8+3
7
2
=16+6\sqrt{7} +2*(8-3\sqrt{7} )=16+6
7
+2∗(8−3
7
)
=16+6\sqrt{7} +16-6\sqrt{7}=16+6
7
+16−6
7
=32=32
∴ 3232
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