Question

if x=3+√8 and y=3-√8 then 1/x²+1/y²=​

Answer 1

$1 \div {x}^{2} + 1 \div {y}^{2} \\ = 1 \div (3 + \sqrt{8} ) ^{2} + 1 \div (3 - \sqrt{8} ) ^{2} \\ =( 1 \div 9 + 6 \sqrt{8} + 8) + (1 \div 9 - 6 \sqrt{8} + 8) \\ = (1 \div 17 + 6 \sqrt{8} ) + (1 \div 17 - 6 \sqrt{8} )$

Answer 2

answer is 34

I hope it's help you plz like and mark me on ☺Brainliest❤❤❤