If x = 3 + √8, then find the value of (x^2) +(1/ x^2)
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Answered by
1
Answer:
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Step-by-step explanation:
x = 3+ √8
x = (3+√8)(3-√8) / (3-√8)
x = (9 -8) / (3-√8)
x = 1/ (3 -√8)
Or we can write 1/x = (3-√8)
Put the value and find out
x² +(1/x²) = x² + (1/x)²
So x² + 1/ x² = (3 +√8)² + (3 -√8)²
= 9+6√8+8 + 9–6√8+8
= 34. Ans.
Answered by
1
Answer:
x = 3+√8.....(I)
1/x = 3-√8/3^2-√8^2
1/x = 3-√8.....(ii)
x+1/x = (3+√8) (3-√8)
x+1/x = 6
x^2+1/x^2
=(x+1/x)^2 -2x.1/x
=6^2 - 2
=36-2
=34
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