Math, asked by syonbro, 8 months ago

If x = 3 + √8, then find the value of (x^2) +(1/ x^2)

Answers

Answered by PreshthaRamchandani
1

Answer:

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Step-by-step explanation:

x = 3+ √8

x = (3+√8)(3-√8) / (3-√8)

x = (9 -8) / (3-√8)

x = 1/ (3 -√8)

Or we can write 1/x = (3-√8)

Put the value and find out

x² +(1/x²) = x² + (1/x)²

So x² + 1/ x² = (3 +√8)² + (3 -√8)²

= 9+6√8+8 + 9–6√8+8

= 34. Ans.

Answered by moupiyamitra860
1

Answer:

x = 3+√8.....(I)

1/x = 3-√8/3^2-√8^2

1/x = 3-√8.....(ii)

x+1/x = (3+√8) (3-√8)

x+1/x = 6

x^2+1/x^2

=(x+1/x)^2 -2x.1/x

=6^2 - 2

=36-2

=34

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