Question

if x+3=9,x+y=14,y+z=20,then the value of x+y+z is

Answer 1

Answer:

The value of $x+y+z=26$.

Step-by-step explanation:

$x+3=9$ implies $x=9-3=6$

given $x+y=14$, substituting the value of $x=6$ we get

         $6+y=14$ implies $y=14-6=8$

also given $y+z=20$, substituting the value of $y=8$ we get

                 $8+z=20$   that is   $z=12$.

Hence we get

$x=6, y=8, z=12$

thus $x+y+z=6+8+12=26$.

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