Question

if (x-3) & (x-1/3) are both factors of ax^2+5x+b show a=b

Answer 1

hi bro!

Here is your Answer!

(x-3) & ( x-1/3) factor of

ax^2 +5x +b

so

put the value of X = 3 in equation

we get

=> a(3)^2 +5×3 + b =0

=> 9a + 15 +b = 0............(1)

Now put X = 1/3 in equation

we get

a/9+5/3 +b = 0...........(2)

solve equation 1 & 2

substract the equation

=> 9a-a/9+b -b = -15+5/3

=> 9a-a/9 = -15+5/3

taking both side LCM

=> (81a-a)/9 = (-45+5)/3

=> 80a/9 = -40/3

=> a = (-40×9)/80×3

=> a = -3/2

now put the value of a

=> 9× -3/2 +15 +b =0

=> b = (27/2) - 15

=> b = (27-30)/2

=> b = -3/2

hence proved
A= B

Hope it's helpful ✌✌