If (x-3) and [ x - 1/3] and both are factors of ax 2 + 5x + b , then show that a = b.
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p(x) = ax² + 5x + b
Given that, ( x – 3 ) and ( x – 1/3 ) are factors of given polynomial.
Therefore, ( x – 3 ) ( x – 1/3 )
= x² + [ 3 + ( 1 / 3 ) ] + 1
= x² + ( 10 / 3 ) x + 1
Now ,
= – coefficient of x / coefficient of x²
=> –5 / a = 10 / 3
10a = – 5 × 3
a = –15 / 10
a = –3 / 2
= constant term / coefficient of x²
=> b / a = 1
a = b
Hence, proved.
p(x) = ax² + 5x + b
Given that, ( x – 3 ) and ( x – 1/3 ) are factors of given polynomial.
Therefore, ( x – 3 ) ( x – 1/3 )
= x² + [ 3 + ( 1 / 3 ) ] + 1
= x² + ( 10 / 3 ) x + 1
Now ,
= – coefficient of x / coefficient of x²
=> –5 / a = 10 / 3
10a = – 5 × 3
a = –15 / 10
a = –3 / 2
= constant term / coefficient of x²
=> b / a = 1
a = b
Hence, proved.
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