If (x-3) and x-1/3 are both factors of ax 2 +5x+b , show that a=b
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Answered by
5
first multiply (x-3) and (x-1/3)
hence, x^2-10/3x+1 now compare both equations
a/1=+5/-10/3=b/1
a=b=-3/2
hence, x^2-10/3x+1 now compare both equations
a/1=+5/-10/3=b/1
a=b=-3/2
Answered by
0
Answer:
Factor = (x -3)
x=3
Put values:-
a(3)² + 5(3) + b = 0
a(9) + 15 + b = 0
9a + 15 + b = 0
9a + b = -15 -----》(1)
Factor = (x-1/3)
x = 1/3
Put values:-
a(1/3)² + 5(1/3) + b = 0
a(1/9) + 5/3 + b = 0
a/9 + b = -5/3
a+9b/9 = -5/3
a + 9b = -5/3 × 9
a + 9b = -5 × 3
a + 9b = -15 --------》(2)
Solving equation (1) and (2)
9a + b = a + 9b
9a - a = 9b - b
8a = 8b
Hence a = b is showed here.
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