Question

If x – 3 and x - 1/3 are both factors of px root 2 + 5x + r, then show that p = r.

Answer 1

Answer:

$(x - 3)(x - \frac{1}{3} ) = {x}^{2} - \frac{10}{3} x + 1 =$

comparing it with given polynomial

$\frac{p}{1} = \frac{5}{ - \frac{10}{3} } = \frac{r}{1}$

$p = - \frac{5 \times 3}{10} = - \frac{3}{2}$

$r = - \frac{5 \times 3}{10} = - \frac{3}{2}$

so p = r

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Mark BRAINLIEST if this is helpful to you. Thanks