if (x-3) and(x-1/3)are both the factiors of ax^2+5x+b then show that a=b
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since x-3 is a factor of the given EQ.
therefore X=3 is the solution
ax²+5x+b=0
a(3)²+5(3)+b=0
9a+15+b=0
9a+b=-15......(i)
since x-1/√3 is a factor of the given EQ.
therefore X=1/√3 is the solution
a(1/√3)²+5(1/√3)+b=0
a/3+5/√3+b=0
taking LCM
a+5√3+3√3b=0
a+3√3b=-5√3
multiplying by 9
9a+27√3b=-45√3....(ii)
now you can solve these 2 eq to get value of a and b
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