if x-3 and x-1/3 are the factors of ax^2+ 5x+b, show that a=b
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shiva198:
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(x-3) and (x -1/3)are factors of ax^2 + 5x + b
f ( x ) = a x^2 + 5x + b
f( 3 )= 0 and f( 1/3 ) = 0
f( 3 ) = a ( 3) ^2 + 5 * 3 + b = 0
9 a + 15 + b = 0
9a + b = -15 --------------------------1
f( 1/ 3 ) = a ( 1/3 ) ^ 2 + 5 * 1/3 + b = 0
a / 9 + 5 / 3 + b= 0
a / 9 + b = - 5/ 3
a + 9 b = - 5 * 9 / 3
a + 9 b = - 15--------------------------2
9a + b = a + 9 b
9a - a = 9b - b
8a = 8 b
a = b
HENCE PROVED
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