Question

If x = -3 and x = 2/3 are solutions of quadratic equation mx2 + 7x + n = 0, find the values of m and n.​

Answer 1

Answer:

m=3,n=-6

Step-by-step explanation:

Given equation,mx^2+7x+n=0

roots are,-3,2/3

In a quadratic equation ax^2+bx+c=0

sum of roots=-b/a

product of roots=c/a

Therefore,

-3+2/3=-7/m

(-9+2)/3=-7/m

-7/3=-7/m

m=3,

(-3)(2/3)=n/m

-3=n/m

n=-3m

n=-3(2)

n=-6

Answer 2

Answer:

m = 3 , n = -6

Step-by-step explanation:

Check out the attachment for more c;ear explaination.

Hope it helps :)