Question

If x=-3 and x=3/4 are solutions of the quadratic equation mx^2+9x+n=0, find the value of m and n.​​

Answer 1

Answer:

Solution

Px(x-3) + 9 = 0

px2-3px+9=0

a=p , b=-3p , c=9

b2-4ac= (-3p)2-4(p)(9)

=9p2-36p

for having equal roots

b2-4ac = 9p2-36p = 0

9p2-36p = 0

9p(p-4) = 0

9p=0 (or) p-4=0

p=0(rejected) or p=4

Answer 2

Answer:

p=4 is ans

Step-by-step explanation:

hope this will help you❤❤